题解 | #判断子序列#

#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param S string字符串 
# @param T string字符串 
# @return bool布尔型
#
class Solution:
    def isSubsequence(self , S: str, T: str) -> bool:
        # write code here
        s_size=len(S)
        t_size=len(T)
        dp=[[0 for i in range(t_size+1)] for j in range(s_size+1)]
        dp[0][0]=1
        for i in range(t_size+1):
            dp[0][i]=1
        for i in range(1,s_size+1):
            for j in range(1,t_size+1):
                if(S[i-1]==T[j-1]):
                    dp[i][j]=dp[i-1][j-1] or dp[i][j-1]
                else:
                    
                    dp[i][j]=dp[i][j-1]
                print('i',i,'j',j)
        if(dp[s_size][t_size]):
            return True
        return False