C 语言实例 - 实现简单的计算器

实现加减乘除计算。

实例

# include <stdio.h>

int main() {

    char operator;
    double firstNumber,secondNumber;

    printf("输入操作符 (+, -, *,): ");
    scanf("%c", &operator);

    printf("输入两个数字: ");
    scanf("%lf %lf",&firstNumber, &secondNumber);

    switch(operator)
    {
        case '+':
            printf("%.1lf + %.1lf = %.1lf",firstNumber, secondNumber, firstNumber + secondNumber);
            break;

        case '-':
            printf("%.1lf - %.1lf = %.1lf",firstNumber, secondNumber, firstNumber - secondNumber);
            break;

        case '*':
            printf("%.1lf * %.1lf = %.1lf",firstNumber, secondNumber, firstNumber * secondNumber);
            break;

        case '/':
            printf("%.1lf / %.1lf = %.1lf",firstNumber, secondNumber, firstNumber / secondNumber);
            break;

        // operator doesn't match any case constant (+, -, *, /)
        default:
            printf("Error! operator is not correct");
    }

    return 0;
}

输出结果为：

输入操作符 (+, -, *,): *
输入两个数字: 4 5
4.0 * 5.0 = 20.0