$(bar) is the correct one, if you type $bar, make will think $b is a variable, and "ar" is astring.But $b isn't define, it will be a space.
点赞 评论

相关推荐

小狗吃臭臭:差不多也就这样了,估计再多写也就是造假了
点赞 评论 收藏
分享
牛客网
牛客企业服务