题解 | #根据状态转移图实现时序电路#
根据状态转移图实现时序电路
https://www.nowcoder.com/practice/e405fe8975e844c3ab843d72f168f9f4
`timescale 1ns/1ns module seq_circuit( input C , input clk , input rst_n, output wire Y ); reg [1:0] cur_state; reg [1:0] nex_state; always@(posedge clk or negedge rst_n)begin if(!rst_n) cur_state <= 2'b00; else cur_state <= nex_state; end always@(*)begin case(cur_state) 2'b00: nex_state = (C == 1)? 2'b01 : 2'b00; 2'b01: nex_state = (C == 1)? 2'b01 : 2'b11; 2'b10: nex_state = (C == 1)? 2'b10 : 2'b00; 2'b11: nex_state = (C == 1)? 2'b10 : 2'b11; default: nex_state = 2'b00; endcase end assign Y = ((cur_state == 2'b11) | (cur_state == 2'b10 & C == 1)) ? 1'b1 : 1'b0; endmodule