题解 | #计算某字符出现次数#

#include <stdio.h>
#include <string.h>
int main() {
    
    char str[1000];
    char ch1;
    char ch2;
    int count =0;
    int i=0;
    while( (ch1 = getchar()) != '\n')
    {
        str[i++] = ch1;
    }
    ch2 = getchar();

    for(int i=0;i<strlen(str);i++)
    {
        if((ch2>=65) && (ch2<=90))
        {   
            if(str[i]==ch2+32)
            count++;
        }

        if((ch2>= 97) &&(ch2<=122))
        {
            if(str[i]==ch2-32)
            count++;
        }

        if(str[i] == ch2)
        {
            count++;
        }
    }

    printf("%d\n",count);

    return 0;
}