题解 | #Johnson Counter#
Johnson Counter
https://www.nowcoder.com/practice/7ee6e9ed687c40c3981d7586a65bc22d
`timescale 1ns/1ns
module JC_counter(
input clk ,
input rst_n,
output reg [3:0] Q
);
//最低位取反移到最高位即可
always@(posedge clk or negedge rst_n)
if(!rst_n) Q <= 4'b0;
else Q <= {~Q[0],Q[3:1]};
endmodule
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