题解 | #人民币转换#
人民币转换
http://www.nowcoder.com/practice/00ffd656b9604d1998e966d555005a4b
具体注释写在code中
#include<stdio.h> #include<string.h> int main(){ char up_digit[9][5] = {"壹","贰","叁","肆","伍","陆","柒","捌","玖"}; char up_unit[14][5] = {"仟","佰","拾","亿","仟","佰","拾","万","仟","佰","拾","元","角","分"}; double money; scanf("%lf",&money); long money_tmp = (long)(money*1000); long r = money_tmp%10; if(r>5) money_tmp = money_tmp/10+1; else money_tmp = money_tmp/10; int num[100]; int idx1 = 0; while(money_tmp>0){ num[idx1++] = money_tmp%10; money_tmp = money_tmp/10; } char out[100]; int offset = 0; for(int i = 0;i<idx1;i++){ // 分角处理 if(num[0]==0&&num[1]==0 && i==0){ offset += sprintf(out+offset,"%s","整"); i = 1; continue; } if(i<=1){ // 分 角不加零 if(num[i]==0) continue; else{ offset += sprintf(out+offset,"%s",up_unit[13-i]); offset += sprintf(out+offset,"%s",up_digit[num[i]-1]); continue; } } // 四个为一组(最小单位输出) if(i==2){ offset += sprintf(out+offset,"%s","元"); if(num[i]!=0) offset += sprintf(out+offset,"%s",up_digit[num[i]-1]); continue; } else if(i==6){ offset += sprintf(out+offset,"%s","万"); if(num[i]!=0) offset += sprintf(out+offset,"%s",up_digit[num[i]-1]); continue; } else if(i==10){ offset += sprintf(out+offset,"%s","亿"); if(num[i]!=0) offset += sprintf(out+offset,"%s",up_digit[num[i]-1]); continue; } // 其他位处理 if(num[i]==0){ // 先处理该位为0的情况 if(num[i-1]!=0){ // 非连续零则加零 offset += sprintf(out+offset,"%s","零"); continue; } else{ continue; } } else{ if((i==3||i==7||i==11)&&num[i]==1){ // 每一组上的拾位单独处理 offset += sprintf(out+offset,"%s","拾"); } else{ offset += sprintf(out+offset,"%s",up_unit[13-i]); offset += sprintf(out+offset,"%s",up_digit[num[i]-1]); } } } offset+=sprintf(out+offset,"%s","币民人"); char out1[100] = {0}; int k = 0; for(int i=offset-1;i>=0;i-=3){ // 逆序输出--注意三个字节装一个汉字 out1[k+2] = out[i]; out1[k+1] = out[i-1]; out1[k] = out[i-2]; k+=3; } printf("%s",out1); return 0; }