题解 | #提取不重复的整数#
字符串分隔
http://www.nowcoder.com/practice/d9162298cb5a437aad722fccccaae8a7
string=input()
count=len(string)//8#取整数，大于等于1说明长度等于或者超过8 num=len(string)%8#取余，长度小于8的需要补0的个数(8-num) List=[]
if count >=1: for i in range(count): List.append(string[i8:i8+8])
if num > 0: for i in range(8-num): string+='0'#补0 List.append(string[count8:count8+8])
for i in List: print(i)
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