题解 | #2的n次方计算#
2的n次方计算
http://www.nowcoder.com/practice/35a1e8b18658411388bc1672439de1d9
#include<stdio.h>
#include<math.h>
int main()
{
int a;
while(scanf("%d",&a)!=EOF)
{
printf("%ld\n",(long)pow(2,a));
}
return 0;
}
2的n次方计算
http://www.nowcoder.com/practice/35a1e8b18658411388bc1672439de1d9
#include<stdio.h>
#include<math.h>
int main()
{
int a;
while(scanf("%d",&a)!=EOF)
{
printf("%ld\n",(long)pow(2,a));
}
return 0;
}
相关推荐