求1+2+3+...+n
求1+2+3+...+n
https://www.nowcoder.com/practice/7a0da8fc483247ff8800059e12d7caf1?tpId=13&&tqId=11200&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking
递推公式：f(n) = f(n-1) + n
递归终止条件：f(1) = 1
public class Solution {
public int Sum_Solution(int n) {
if (n == 1) {
return 1;
} else {
return n + Sum_Solution(n-1);
}
}
} 
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