题解 | #跳台阶#
跳台阶
http://www.nowcoder.com/questionTerminal/8c82a5b80378478f9484d87d1c5f12a4
class Solution:
def jumpFloor(self, number):
if number==0:
return 0
elif number==1:
return 1
elif number==2:
return 2
else:
a,b=1,2
while number>2:
a,b=b,a+b
number-=1
return b
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