Read Number in Chinese(PAT)

1.题目描述

Given an integer with no more than 9 digits, you are supposed to read it in the traditional Chinese way. Output “Fu” first if it is negative. For example, -123456789 is read as “Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai ba Shi jiu”. Note: zero (“ling”) must be handled correctly according to the Chinese tradition. For example, 100800 is “yi Shi Wan ling ba Bai”.
给定一个不超过9位数的整数，你应该用传统的中文方式阅读它。如果是负值的话输出“Fu”。例如，-123456789被解读为“Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai ba Shi jiu”。注：零(“ling”)必须按照中国传统正确处理。例如，100800是“yi Shi Wan ling ba Bai”。

2.输入描述:

Each input file contains one test case, which gives an integer with no more than 9 digits.
每个输入文件包含一个测试用例，它给出的整数不超过9位数。

3.输出描述:

For each test case, print in a line the Chinese way of reading the number. The characters are separated by a space and there must be no extra space at the end of the line.
对于每个测试用例，用一行打印中文读取数字的方式。字符用空格分隔，行尾不能有额外的空格。

4.输入例子:

-123456789

5.输出例子:

Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai ba Shi jiu

6.源代码：

#include<stdio.h>
#include<string.h>
int main()
{
	char num[11]="\0",str[100]="\0";
	scanf("%s",&num);
	int i=0,len=strlen(num);
	if(num[0]=='-')//判断正负
	{
		i=1;
		len--;
		strcat(str,"Fu ");
	}
	if(strcmp(num,"0")==0)//判断是否为零
		strcat(str,"ling ");
	while(len)
	{
		switch(num[i])//翻译数字为拼音
		{
			case '0':
				if(num[i+1]!='0'&&len%4!=1)//判断是否添加ling
					strcat(str,"ling ");
				break;
			case '1':strcat(str,"yi ");break;
			case '2':strcat(str,"er ");break;
			case '3':strcat(str,"san ");break;
			case '4':strcat(str,"si ");break;
			case '5':strcat(str,"wu ");break;
			case '6':strcat(str,"liu ");break;
			case '7':strcat(str,"qi ");break;
			case '8':strcat(str,"ba ");break;
			case '9':strcat(str,"jiu ");break;
			default:break;
		}
		if(num[i]!='0')
		{
			switch(len%4)//添加位数拼音
			{
				case 2:strcat(str,"Shi ");break;//十 
				case 3:strcat(str,"Bai ");break;//白
				case 0:strcat(str,"Qian ");break;//千
				default:break;
			}	
		}
		//根据长度len%4的余数来确定位数
		if(len/4==2&&len%4==1)
			strcat(str,"Yi ");//亿
		else
		{	
			if(len/4==1&&len%4==1)
			{
				if(num[i]!='0'||num[i-1]!='0'||num[i-2]!='0'||num[i-3]!='0')
					strcat(str,"Wan ");//万
				else
					if(num[i+1]!='0')
						strcat(str,"ling ");
			}
		}
		len--;
		i++;
	}
	len=strlen(str);
	for(i=0;i<len-1;i++)
		printf("%c",str[i]);
	return 0;
}