SELECT qd.difficult_level, (SUM(IF (qpd.result = 'right', 1, 0)) / COUNT(*)) AS correct_rate FROM user_profile up INNER JOIN question_practice_detail qpd ON up.device_id = qpd.device_id INNER JOIN question_detail qd ON qpd.question_id = qd.question_id WHERE university = '浙江大学...