题1:5进制和10进制的转换 #include <bits/stdc++.h> using namespace std; unordered_map<char, int> m1 = {{'o', 0}, {'y', 1}, {'e', 2}, {'a', 3}, {'s', 4}}; unordered_map<int, char> m2 = {{0, 'o'}, {1, 'y'}, {2, 'e'}, {3, 'a'}, {4, 's'}}; //5转10 int ftot(string& s){ int i = s.size() ...