9.29奇安信笔试
题1：5进制和10进制的转换
#include <bits/stdc++.h>
using namespace std;
unordered_map<char, int> m1 = {{'o', 0}, {'y', 1}, {'e', 2}, {'a', 3}, {'s', 4}};
unordered_map<int, char> m2 = {{0, 'o'}, {1, 'y'}, {2, 'e'}, {3, 'a'}, {4, 's'}};
//5转10
int ftot(string& s){
int i = s.size() - 1;
int res = 0;
for(auto& t : s){
res += m1[t] * pow(5, i);
i--;
}
return res;
}
//10转5
string ttof(string& s){
int t = stoi(s);
string res;
while(t){
res += m2[t % 5];
t /= 5;
}
reverse(res.begin(), res.end());
return res;
}
int main(){
int n;
cin >> n;
while(n--){
string s;
cin >> s;
if(!(s[0] >= '0' && s[0] <= '9')){
cout << ftot(s) << endl;
}
else{
cout << ttof(s) << endl;
}
}
return 0;
} 题2：有多少种方法从左上角走到右下角，dfs，代码忘记存了 题3：给你一个只包含01的字符串，统计有多少个子串满足连续1的个数是最大，不会，只能暴力，当然是过不了了QAQ
#include <bits/stdc++.h>
using namespace std;
const int MOD = 1e10 + 7;
int res = 0;
int total = 0;
int onesum(const string& s){
int i = 0;
int res = 0;
int l = 0;
for(int i = 0; i != s.size(); i++){
if(s[i] == '1') l++;
else l = 0;
res = max(res, l);
}
return res;
}
int check(const string s, int sum){
int i = 0;
int res = 0;
int l = 0;
for(int i = 0; i != s.size(); i++){
if(s[i] == '1') l++;
else l = 0;
res = max(res, l);
}
return res == sum;
}
void dfs(string& s, int index){
if(index == s.size()){
return;
}
for(int i = index; i != s.size(); i++){
if(check(s.substr(index, i - index + 1), total)){
res = (res + 1) % MOD;
}
dfs(s, i + 1);
}
}
int main(){
int n;
cin >> n;
string s;
cin >> s;
total = onesum(s);
dfs(s, 0);
cout << res << endl;
return 0;
} 
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