题解 | KiKi和酸奶
KiKi和酸奶
https://www.nowcoder.com/practice/c7721f3a1b1a47a783974453e82cadbb
#include <stdio.h> int main() { int n = 0; int m = 0; int h = 0; scanf("%d %d %d",&n,&h,&m); printf("%d\n", (n * h - m) / h); }
KiKi和酸奶
https://www.nowcoder.com/practice/c7721f3a1b1a47a783974453e82cadbb
#include <stdio.h> int main() { int n = 0; int m = 0; int h = 0; scanf("%d %d %d",&n,&h,&m); printf("%d\n", (n * h - m) / h); }
相关推荐