题解 | 二叉树的后序遍历
二叉树的后序遍历
https://www.nowcoder.com/practice/1291064f4d5d4bdeaefbf0dd47d78541
import java.util.*; /* * public class TreeNode { * int val = 0; * TreeNode left = null; * TreeNode right = null; * public TreeNode(int val) { * this.val = val; * } * } */ public class Solution { /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param root TreeNode类 * @return int整型一维数组 */ public int[] postorderTraversal (TreeNode root) { // write code here List<Integer> post = new ArrayList<>(); // 后序遍历:左、右、根 postOrder(root, post); return post.stream().mapToInt(i -> i).toArray(); } private void postOrder(TreeNode root, List<Integer> post) { if (root == null) return; postOrder(root.left, post); postOrder(root.right, post); post.add(root.val); } }
线性表基础 文章被收录于专栏
链表、递归、栈