题解 | 日期类

#include<iostream>
#include<stdio.h>
using namespace std;
bool leapyear(int n){
	return n%4==0&&n%100!=0||n%400==0;
}
int main(){
	int m;
	int Y,M,D;
	cin>>m;
	while(m){
		cin>>Y>>M>>D;
		int month[]={31,leapyear(Y)?29:28,31,30,31,30,31,31,30,31,30,31};
		if(D==month[M-1]){
			if(M==12){
				Y++;
				M=1;
				D=1;
			}
			else{
				M++;
				D=1;
			}
		}
		else{
			D++;
		}
		printf("%04d-%02d-%02d\n",Y,M,D);
		m--;
	}
}