题解 | A+B

#include <bits/stdc++.h>
using namespace std;

int main() {
	string A, B;
	while (cin >> A >> B) {
		long long a = 0;
		long long b = 0;
		for(int i = 0; i < A.size(); i++) {
			if (A[i] == ',' || A[i] == '-') {
				continue;
			}
			a = a * 10 + (A[i] - '0');
		}
		if (A[0] == '-') {
			a = -a;
		}
		for(int j = 0; j < B.size(); j++) {
			if (B[j] == ',' || B[j] == '-') {
				continue;
			}
			b = b * 10 + (B[j] - '0');
		}
		if (B[0] == '-') {
			b = -b;
		}
		long long c = a + b;
		cout << c << endl;
	}
	return 0;
}

数据量不大，可以用long long 解决