题解 | #查询连续入住多晚的客户信息？#

SELECT
    B.user_id,
    B.room_id,
    A.room_type,
    DATEDIFF (checkout_time, checkin_time) AS days
FROM
    guestroom_tb A
    JOIN checkin_tb B ON A.room_id = B.room_id
WHERE
    DATEDIFF (checkout_time, checkin_time) > 1
ORDER BY
    DATEDIFF (checkout_time, checkin_time)ASC,B.room_id ASC,B.user_id DESC