题解 | #实现二叉树先序,中序和后序遍历#
实现二叉树先序,中序和后序遍历
https://www.nowcoder.com/practice/a9fec6c46a684ad5a3abd4e365a9d362
import java.util.*; /* * public class TreeNode { * int val = 0; * TreeNode left = null; * TreeNode right = null; * public TreeNode(int val) { * this.val = val; * } * } */ public class Solution { /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param root TreeNode类 the root of binary tree * @return int整型二维数组 */ public int[][] threeOrders (TreeNode root) { // write code here List<Integer> list1 = new ArrayList<>(); List<Integer> list2 = new ArrayList<>(); List<Integer> list3 = new ArrayList<>(); xianxu(root, list1); zhongxu(root, list2); houxu(root, list3); int[][] res = new int[3][list1.size()]; for (int i = 0; i < list1.size(); i++) { res[0][i] = list1.get(i); res[1][i] = list2.get(i); res[2][i] = list3.get(i); } return res; } private void xianxu(TreeNode root, List<Integer> list){ if (root == null) { return; } list.add(root.val); xianxu(root.left, list); xianxu(root.right, list); } private void zhongxu(TreeNode root, List<Integer> list){ if (root == null) { return; } zhongxu(root.left, list); list.add(root.val); zhongxu(root.right, list); } private void houxu(TreeNode root, List<Integer> list){ if (root == null) { return; } houxu(root.left, list); houxu(root.right, list); list.add(root.val); } }