题解 | #牛客的伙伴们#
牛客的伙伴们
https://www.nowcoder.com/practice/a41ea5591c40479dbf90d3329a03fb62
#zip 函数是可以接收多个可迭代对象,然后把每个可迭代对象中的第i个元素组合在一起,形成一个新的迭代器,类型为元组 friends = ['NiuMei', 'NiuKele', 'NiuNeng'] question = [3, 4, 5, 8] z = list(zip(friends,question)) print(z)