题解 | #删除字符串中出现次数最少的字符#
删除字符串中出现次数最少的字符
https://www.nowcoder.com/practice/05182d328eb848dda7fdd5e029a56da9
x = str(input())
mp = [0 for _ in range(26)]
for c in x:
c = ord(c) - ord('a')
mp[c] += 1
mi = int(999)
for i in range(26):
if mp[i] != 0:
mi = min(mp[i], mi)
for i in range(26):
if mp[i] == mi:
x = x.replace(chr(ord('a')+ i),'')
print(x)
删除最小的数值的元素
