题解 | #链表内指定区间反转#
链表内指定区间反转
https://www.nowcoder.com/practice/b58434e200a648c589ca2063f1faf58c
/** * struct ListNode { * int val; * struct ListNode *next; * }; */ /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param head ListNode类 * @param m int整型 * @param n int整型 * @return ListNode类 */ struct ListNode* reverseBetween(struct ListNode* head, int m, int n ) { // write code here if(head==NULL||head->next==NULL) return head; if(m==n) return head; /* *把第m个节点后的所有节点依次插入到第m个位置前 */ struct ListNode* dummy = (struct ListNode*)malloc(sizeof(struct ListNode)); dummy->val = 0; dummy->next = head; struct ListNode* pPre = dummy; struct ListNode* pCur = head; //tmp指向要发转到最前的节点 struct ListNode* pTmp = NULL; for(int i=0; i<m-1; i++) { pPre = pPre->next; pCur = pCur->next; } for(int i=0; i<n-m; i++) { pTmp = pCur->next; pCur->next = pCur->next->next; pTmp->next = pPre->next; pPre->next = pTmp; } return dummy->next; }