题解 | #四则运算#
四则运算
https://www.nowcoder.com/practice/9999764a61484d819056f807d2a91f1e
def compute(s):
    #数字
    temp_num = ""
    #运算符
    comp = []
    i=0
    l = len(s)
    while i< l:
        if s[i] in ['+','-','*','/']:
            comp.append(s[i])
            temp_num +=" "
        elif s[i] in ['(','[','{']:
            find_open = dict(zip(['(','[','{'],[')',']','}']))
            flag = 1
            j = i+1
            while j < len(s) :
                if s[j] == s[i]:
                    flag +=1
                elif s[j] == find_open[s[i]]:
                    flag -=1
                if flag == 0:
                    break
                j += 1
            temp_num += str(compute(s[i+1:j]))
            i = j
        else:
            temp_num +=s[i]
        
        i+=1
    num =[eval(i) for i in temp_num.split()]
    if len(num) == len(comp):
        #有符号位
        num[0] = -num[0] if s[0] == '-' else num[0]
        comp = comp[1:]
    #入栈运算
    que = [num[0]]
    for i in range(len(comp)):
        if comp[i] == '+':
            que.append(num[i+1])
        elif comp[i] == '-':
            que.append(-num[i+1])
        elif comp[i] == '*':
            temp = que.pop()
            que.append(temp*num[i+1])
        elif comp[i] == '/':
            temp = que.pop()
            que.append(temp/num[i+1])
    
    return sum(que)
s = input()
out = compute(s)
print(int(out))
 投递福建联通等公司10个岗位
投递福建联通等公司10个岗位