题解 | #牛牛的矩阵相加#
牛牛的矩阵相加
https://www.nowcoder.com/practice/730b90507602412fac90a3f106bfa0cd
list = [[1,2,3], [4,5,6], [7,8,9]] n = int(input()) ls = [[],[],[]] k = 0 for i in list: for j in list[k]: ls[k].append(n*j) k += 1 print(ls)
牛牛的矩阵相加
https://www.nowcoder.com/practice/730b90507602412fac90a3f106bfa0cd
list = [[1,2,3], [4,5,6], [7,8,9]] n = int(input()) ls = [[],[],[]] k = 0 for i in list: for j in list[k]: ls[k].append(n*j) k += 1 print(ls)
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