题解 | #牛牛的矩阵相加#
牛牛的矩阵相加
https://www.nowcoder.com/practice/730b90507602412fac90a3f106bfa0cd
list_er = [[1,2,3],[4,5,6],[7,8,9]]
n = int(input())
out_list = []
for x in list_er:
out_list.append([m*n for m in x])
print(out_list)
2023-08-24 10:03 西北农林科技大学 测试开发
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