题解 | #数值的整数次方#

class Solution {
public:
    double Power(double base, int exponent) {
        if(exponent==0)
            return 1;
        if(exponent==1)
            return base;
        if(exponent>0)
            return base*Power(base, exponent-1);
        if(exponent<0)
            return (1/base)*Power(base, exponent+1); 
        return 0;
    }
};