题解 | #数值的整数次方#
数值的整数次方
https://www.nowcoder.com/practice/1a834e5e3e1a4b7ba251417554e07c00
class Solution {
public:
double Power(double base, int exponent) {
if(exponent==0)
return 1;
if(exponent==1)
return base;
if(exponent>0)
return base*Power(base, exponent-1);
if(exponent<0)
return (1/base)*Power(base, exponent+1);
return 0;
}
};
。
