题解 | #牛牛的矩阵相加#
牛牛的矩阵相加
https://www.nowcoder.com/practice/730b90507602412fac90a3f106bfa0cd
n = int(input()) matrix = [[1,2,3],[4,5,6],[7,8,9]] for i in range(len(matrix)): for j in range(len(matrix[0])): matrix[i][j] *= n print(matrix)
牛牛的矩阵相加
https://www.nowcoder.com/practice/730b90507602412fac90a3f106bfa0cd
n = int(input()) matrix = [[1,2,3],[4,5,6],[7,8,9]] for i in range(len(matrix)): for j in range(len(matrix[0])): matrix[i][j] *= n print(matrix)
相关推荐