题解 | #2021年11月每天的人均浏览文章时长#
2021年11月每天的人均浏览文章时长
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select date(in_time) as dt, round(sum(TIMESTAMPDIFF(second,in_time,out_time))/count(distinct(uid)),1) as avg_viiew_len_sec from tb_user_log where DATE_FORMAT(in_time,"%Y-%m")='2021-11' and artical_id!=0 group by date(in_time) order by avg_viiew_len_sec