题解 | #平均播放进度大于60%的视频类别#

select b.tag,
   concat(round(sum(if(TIMESTAMPDIFF(second,start_time,end_time)>=duration,duration,TIMESTAMPDIFF(second,start_time,end_time)))/sum(duration)*100,2),"%") as avg_play_progress
from tb_user_video_log a
left join tb_video_info b
on a.video_id=b.video_id
group by a.video_id
having avg_play_progress>60
order by avg_play_progress desc
#之前在没改时间戳那里的时候自测运行对了，但是保存就错了，多了一个旅游类的。在计算时我们只需要取second就好，要用到TIMESTAMPDIFF函数