题解 | #走方格的方案数#
走方格的方案数
https://www.nowcoder.com/practice/e2a22f0305eb4f2f9846e7d644dba09b
#include <iostream> #include <vector> #include "bits/stdc++.h" using namespace std; int uniquePaths(int m, int n) { vector<vector<int>> dp(m, vector<int>(n, 0)); for (int i = 0; i < m; i++) dp[i][0] = 1; for (int j = 0; j < n; j++) dp[0][j] = 1; for (int i = 1; i < m; i++) { for (int j = 1; j < n; j++) { dp[i][j] = dp[i - 1][j] + dp[i][j - 1]; } } return dp[m - 1][n - 1]; } int main() { int m,n; cin>>m>>n; int res=uniquePaths(m+1,n+1); cout<<res; } // 64 位输出请用 printf("%lld")