题解 | #计算日期到天数转换#

#include <stdio.h>

int main() {
    int day_s[12] = {31,28,31,30,31,30,31,31,30,31,30,31};
    int year = 0;
    int month = 0;
    int day = 0;
    int out = 0;
    scanf("%d %d %d", &year, &month, &day);
    if(year % 4 == 0 && year % 100 != 0 || year % 400 == 0) //闰年判断
    {
        day_s[1] = 29;
    }
    else {
        day_s[1] = 28;
    }
    for(int i = 0; i<month-1; i++)
    {
        out += day_s[i];
    }
    printf("%d",out+day);
    
    return 0;
}