题解 | #Johnson Counter#
Johnson Counter
https://www.nowcoder.com/practice/7ee6e9ed687c40c3981d7586a65bc22d
`timescale 1ns/1ns
module JC_counter(
input clk ,
input rst_n,
output reg [3:0] Q
);
always @(posedge clk or negedge rst_n) begin
if(rst_n == 1'b0)
Q <= 4'd0;
else
Q <= {~Q[0],Q[3:1]};
end
endmodule
好有价值！