题解 | #牛牛学数列3#
牛牛学数列3
https://www.nowcoder.com/practice/f65c726d081c4160a9356eabf0dc21d9
#include <stdio.h>
int main()
{
int a,i;
double sum=0,sum1=0;
scanf("%d",&a);
for(i=-1;i<a-1;){
i=i+2;
sum+=1.0/i;
} if(a%2!=0){
for(i=0;-i<a-1;){
i=i-2;
sum1+=1.0/i;
}
}else {
for(i=0;-i<a;){
i=i-2;
sum1+=1.0/i;
}
}printf("%.3f",sum+sum1);
return 0;
}
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