题解 | #识别有效的IP地址和掩码并进行分类统计#

def puip(ip):
    if 1<=ip[0]<=126:
        res[0]+=1
    elif 128<=ip[0]<=191:
        res[1]+=1
    elif 192<=ip[0]<=223:
        res[2]+=1
    elif 224<=ip[0]<=239:
        res[3]+=1
    elif 240<=ip[0]<=255:
        res[4]+=1
    return        

def prip(ip):
    if ip[0]==10 or (ip[0]==172 and 16<=ip[1]<=32) or(ip[0]==192 and ip[1]==168):
        res[6]+=1
    return

def ym(msk):
    val = (msk[0]<<24) + (msk[1]<<16) + (msk[2]<<8) +(msk[3])
    s = bin(val)[2:]
    pos0 = s.find('0') #从左往右找第一次0出现位置
    pos1 = s.rfind('1') #从右往左找第一次1出现位置
    if pos0!=-1 and pos1!=-1 and pos0-pos1==1:
        return True
    return False
 

res = [0,0,0,0,0,0,0]
try:
    while True:
        ip,msk = input().split('~')
        ips = [int(i) for i in filter(None,ip.split('.'))]
        msks = [int(i) for i in filter(None,msk.split('.'))]
        if ips[0]==0 or ips[0]==127:
            continue
        if len(ips)<4 or len(msks)<4:
            res[5]+=1
            continue
        if ym(msks) == True:
            puip(ips)
            prip(ips)
        else:
            res[5]+=1
            
        
except EOFError:
    print(' '.join(str(i) for i in res))