题解 | #扑克牌大小#

from collections import Counter

dmap = {
    "3":3,"4":4,"5":5,"6":6,"7":7,"8":8,"9":9,"10":10,"J":11,"Q":12,"K":13,"A":14,"2":15,"joker":16,"JOKER":17
}

def ifpairj(ss):
    if 16 in ss and 17 in ss:
        return True
    return False

def ifp(ss):
    res = [[],[],[],[]]
    s = dict(Counter(ss))
    for k,v in s.items():
        res[v-1].append(k)
    shunl = []
    shun = 0
    for i in range(len(ss)-1):
        if (ss[i]-ss[i+1] == -1):
            shun+=1
        else:
            if shun >= 5:
                shunl.append(ss[i-4])
            shun = 0
    res = res[:2]+[shunl]+res[2:]
    return res

def run(seq):
    seq1, seq2 = seq.split("-")
    s1 = sorted([dmap[_] for _ in seq1.split()])
    s2 = sorted([dmap[_] for _ in seq2.split()])
    if ifpairj(s1):
        return seq1
    if ifpairj(s2):
        return seq2
    s1 = ifp(s1)
    s2 = ifp(s2)
    res = "ERROR"
    for i in range(4,-1,-1):
        if len(s1[i]) > 0 and len(s2[i]) > 0:
            if max(s1[i]) == max(s2[i]):
                continue
            elif max(s1[i]) > max(s2[i]):
                res = seq1
                break
            else:
                res = seq2
                break
        elif i==4:
            if len(s1[i]) > 0:
                res = seq1
                break
            elif len(s2[i]) > 0:
                res = seq2
                break
        else:
            continue
                
    return res

a  =input().strip()
print(run(a))