题解 | #使用3-8译码器①实现逻辑函数#

`timescale 1ns/1ns

module decoder_38( input E1_n , input E2_n , input E3 , input A0 , input A1 , input A2 ,

output wire Y0_n ,
output wire Y1_n , output wire Y2_n , output wire Y3_n , output wire Y4_n , output wire Y5_n , output wire Y6_n , output wire Y7_n
); wire E ; assign E = E3 & ~E2_n & ~E1_n; assign Y0_n = ~(E & ~A2 & ~A1 & ~A0); assign Y1_n = ~(E & ~A2 & ~A1 & A0); assign Y2_n = ~(E & ~A2 & A1 & ~A0); assign Y3_n = ~(E & ~A2 & A1 & A0); assign Y4_n = ~(E & A2 & ~A1 & ~A0); assign Y5_n = ~(E & A2 & ~A1 & A0); assign Y6_n = ~(E & A2 & A1 & ~A0); assign Y7_n = ~(E & A2 & A1 & A0);

endmodule

module decoder0( input A , input B , input C , output wire L ); wire e1_n=0; wire e2_n=0; wire e3=1;

wire y1n,y2n,y3n,y4n;
wire y5n,y6n,y7n,y0n;

assign L=~(y1n & y3n & y6n & y7n);
    
decoder_38 decoder1(
    .E1_n(0)   ,
    .E2_n(0)   ,
    .E3(1)     ,
    .A0(C)     ,
    .A1(B)     ,
    .A2(A)     ,
    .Y0_n(y0n)   ,  
    .Y1_n(y1n)   , 
    .Y2_n(y2n)   , 
    .Y3_n(y3n)   , 
    .Y4_n(y4n)   , 
    .Y5_n(y5n)   , 
    .Y6_n(y6n)   , 
    .Y7_n(y7n)   
);

endmodule