题解 第二章暴力求解| #日期类#

思路非常简单

即设计一个保存日期的类

在这个类中添加日期自增1和打印日期的功能即可

#include <iostream>
using namespace std;

static const int month[2][13]=
{
    {0,31,28,31,30,31,30,31,31,30,31,30,31},
    {0,31,29,31,30,31,30,31,31,30,31,30,31}
};
static const int year[2]={365,366};

class Date
{
public:
    Date()=default;
    Date(int YY,int MM,int DD):Y(YY),M(MM),D(DD) {}
    Date(const Date &date):Y(date.Y),M(date.M),D(date.D) {}
    ~Date(){}
    void setDate(int YY,int MM,int DD) {Y=YY;M=MM;D=DD;}
    void datePrint(){printf("%04d-%02d-%02d\n",Y,M,D);}
//void datePrint(){printf("%4d-%2d-%2d\n",Y,M,D);}
//如果这样写,则输出不会被0填充,而是被空格填充
    void PlusOneDay();
private:
    int Y=0,M=0,D=0;
};
void Date::PlusOneDay()
{
    int isRun=0;
    if(!(Y%4)&&Y%100||Y%400)
        isRun=1;
    if(D==month[isRun][M])
    {
        D=1,M++;
        if(M==13)
            M=1,Y++;
    }
    else D++;
}

int main()
{
    Date inputDay;
    int inputY,inputM,inputD;
    int repeatTimes=0;
    cin>>repeatTimes;
    while(repeatTimes--)
    {
        cin>>inputY>>inputM>>inputD;
        inputDay.setDate(inputY,inputM,inputD);
        inputDay.PlusOneDay();
        inputDay.datePrint();
    }
    return 0;
}