题解 | #牛客考试分数(二)#
考试分数(二)
http://www.nowcoder.com/practice/f456dedf88a64f169aadd648491a27c1
with avg_sc as (
select job,avg(score) as j_s
from grade
group by job
),
id_job as (
select id,a.job,score,j_s
from grade a
left join avg_sc b
on a.job=b.job
)
select id,job,score
from id_job
where score>j_s
group by id
order by id 
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