根节点到叶子节点的节点值之和等于\ sum sum
二叉树根节点到叶子节点和为指定值的路径
https://www.nowcoder.com/practice/840dd2dc4fbd4b2199cd48f2dadf930a?tpId=117&tags=&title=&diffculty=0&judgeStatus=0&rp=1&tab=answerKey
public ArrayList<ArrayList<Integer>> pathSum (TreeNode root, int sum) {
// write code here
ArrayList<Integer> list = new ArrayList<>();
ArrayList<ArrayList<Integer>> lists = new ArrayList<>();
dfs(lists,list,0,sum,root);
return lists;
}
private void dfs(ArrayList<ArrayList<Integer>> lists, ArrayList<Integer> list,
int sum ,int k,TreeNode root){
if(root==null) return;
sum += root.val;
list.add(root.val);
if(root.left==null && root.right==null){
if(sum==k){
ArrayList<Integer> gg = new ArrayList<>();
for(int l:list){
gg.add(l);
}
//*注意list里面嵌入list的时候 改变里面的list会改变外层list 即添加进去的是引用*
lists.add(gg);
}
list.remove(list.size()-1);
return;
}
dfs(lists,list,sum,k,root.left);
dfs(lists,list,sum,k,root.right);
list.remove(list.size()-1);
}

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