hive查询操作1

select workingExp,company_name from table1 where responsibility like '%hive%' and salary > '8000';
select avg(t1.salary) as new_salary, t2.city_name from table1 t1 right outer join table2 t2 on t1.city_code = t2.city_code group by t2.city_name;
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10-27 17:26
东北大学 Java
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