LeetCode 1. Two Sum

Given an array of integers, return indices of the two numbers such that they add up to a specific target.
You may assume that each input would have exactly one solution, and you may not use the same element twice.
Example:

Given nums = [2, 7, 11, 15], target = 9,

Because nums[0] + nums[1] = 2 + 7 = 9,
return [0, 1].

程序代码

/** * Note: The returned array must be malloced, assume caller calls free(). */
int* twoSum(int* nums, int numsSize, int target) {
    int i=0,j=0;
    int a=-1,b=-1;
    int* ans;
    ans = (int*)malloc(sizeof(int)*2);
    for(i=0;i<numsSize-1;i++)
    {
        for(j=i+1;j<numsSize;j++)
        {
             if((nums[i]+nums[j])==target)
            {
                a = i;
                b = j;
                break;
            }
        }
            if(a>=0&&b>=0)
                break;
    }
    *ans = a;
    *(ans+1) = b;
    return ans;
}