-- 1 select us.gender,count(*) number from (select device_id,mid(profile,15,6) gender,blog_url from user_submit) us group by us.gender; *-- 2 字符串分割 SELECT SUBSTRING_INDEX(profile,',',-1) gender ,count(*) from user_submit group by gender;* -- 3 like + if SELECT if(profile like '%female','female','mal...