DevRoss：# -*- coding: utf-8 -*-
# Created by Ross on 19-4-12
n = int(input())
if n < 1:
exit()
neg = 1 # 表示前面两人都抽不中的概率
c = 0
ps = []
for i in range(n):
p = float(input())
ps.append(p)
i = 0
while i < 100:
if i % 2 == 0: # 轮到小明
p = ps[i % n]
c += neg * p
neg *= (1 - p)
else: # 轮到小华
p = ps[i % n]
neg *= 1 - p
i += 1
print('%.4f' % c)
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