只要先求出最大公约数,再拿这两个数的积除以最大公约数,即可得到最大公倍数#include<iostream>using namespace std;</iostream> int main(){ long n,m,c,multi; long sum=0; cin >> n >> m; multi = n*m; c = n%m; while(c != 0) { n = m; m = c; c = n%m; } sum = multi/m+m; co...