1、差集。 select c.id,c.num from (select a.`村寨id` id, count(1) num from 农户签约详细信息 a group by a.`村寨id`) c left join (select b.`村寨id` id, count(1) num from 房间 b group by b.`村寨id`)d on c.id = d.id where c.num < d.num; SELECT DISTINCT t.id FROM( select a.`村寨id` id, count(1) num from 农户签约详细信息 a group...