在尝试用 TreeSet 实现,但是还是连着 wa 了两次,过了 0 个用例,心态有点爆炸,就提前 5 分钟交卷,结果尿了泡尿,好像检查出自己的问题在 rightEdge 和 leftEdge 没有和 l,r 取并集上,心态更炸裂,这次的题目感觉很简单,前两道题 15 分钟就做完了,第三题看着也不难,不知道大家都咋样?这道题我想的思路是用 treeset 保存所有 max 值的下标,然后判断 l,r 区间内有没有 max 值,有几个 max 值,l, r 区间外有没有 max 值来实现import java.util.Scanner;import java.util.Arrays;import java.util.HashMap;import java.util.TreeSet;import java.util.HashSet;// 注意类名必须为 Main, 不要有任何 package xxx 信息public class Main { public static void main(String[] args) { Scanner in = new Scanner(System.in); // 注意 hasNext 和 hasNextLine 的区别 int n = in.nextInt(), q = in.nextInt(); int[] arr = new int[n]; TreeSet set = new TreeSet<>(); int max_val = 0; for (int i = 0; i arr[i] = in.nextInt(); if (arr[i] > max_val) { max_val = arr[i]; set.clear(); set.add(i + 1); } } while (q-- > 0) { int l = in.nextInt(); int r = in.nextInt(); if (l == 1 && r == n) { if (set.size() == 1) { System.out.println("lose"); System.out.println(r == l ? 2 : r - l + 1); } else { System.out.println("draw"); System.out.println(r == l ? 2 : r - l + 1); } continue; } if (set.ceiling(l) == null || set.floor(r) == null || set.ceiling(l) > r || set.floor(r) System.out.println("win"); long right_edge = set.ceiling(l) == null ? Integer.MAX_VALUE : set.ceiling(l); long left_edge = set.floor(r) == null ? Integer.MIN_VALUE : set.floor(r); long min_size = Math.min(right_edge - l + 1, r - left_edge + 1); System.out.println(min_size == 1 ? 2 : min_size); continue; } // pointing to the same biggest if (set.ceiling(l) != set.floor(r)) { // has additional biggest besides [l, r] if (set.floor(l - 1) != null || set.ceiling(r + 1) != null) { long right_edge = set.ceiling(r + 1) == null ? Integer.MAX_VALUE : set.ceiling(r + 1); long left_edge = set.floor(l - 1) == null ? Integer.MIN_VALUE : set.floor(l - 1); System.out.println("draw"); long min_size = Math.min(Math.max(right_edge, r) - l + 1, r - Math.min(l, left_edge) + 1); System.out.println(min_size == 1 ? 2 : min_size); continue; } else { System.out.println("lose"); System.out.println(r == l ? 2 : r - l + 1); continue; } } else { if (set.floor(l - 1) != null || set.ceiling(r + 1) != null) { long right_edge = set.ceiling(r + 1) == null ? Integer.MAX_VALUE : set.ceiling(r + 1); long left_edge = set.floor(l - 1) == null ? Integer.MIN_VALUE : set.floor(l - 1); System.out.println("draw"); long min_size = Math.min(Math.max(r, right_edge) - l + 1, r - Math.min(l, left_edge) + 1); System.out.println(min_size == 1 ? 2 : min_size); continue; } else { System.out.println("lose"); System.out.println(r == l ? 2 : r - l + 1); continue; } } } }}