选择题太多,编程题很容易 1. 求和1/2,2/3,3/5...前n项和 float seqSum(int n) { // write code here float res(0),fz(1),fm(2); for(int i=0;i<n;i++){ res+=fz/fm; float temp=fz; fz=fm; fm=temp+fm; } return round(res*100)/100;...