select device_id, university, gpa from ( select device_id, university, gpa, ##使用row_number()进行开窗,先按大学分组,再按gpa排序 row_number() over (partition by university order by gpa asc ) rk from user_profile )t1 where rk = 1##取分组内的第一个即为每个学校GPA最...